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Calculate the sum of series of even numbers

Published on Nov 17 2009 // Beginners

Statement: Calculate the sum of series of even numbers from the list of numbers. The length of the list is in memory location 2200H and the series itself begins from memory location 2201H. Assume the sum to be 8 bit number so you can ignore carries and store the sum at memory location 2210H.

Sample problem 1:

2200H= 4H

2201H= 20H

2202H= l5H

2203H= l3H

2204H= 22H

Result 22l0H= 20 + 22 = 42H

= 42H

Source program :

  • LDA 2200H
  • MOV C, A : Initialize counter
  • MVI B, 00H : sum = 0
  • LXI H, 2201H : Initialize pointer
  • BACK: MOV A, M : Get the number
  • ANI 0lH : Mask Bit l to Bit7
  • JNZ SKIP : Don’t add if number is ODD
  • MOV A, B : Get the sum
  • ADD M : SUM = SUM + data
  • MOV B, A : Store result in B register
  • SKIP: INX H : increment pointer
  • DCR C : Decrement counter
  • JNZ BACK : if counter  0 repeat
  • STA 2210H : store sum
  • HLT : Terminate program execution


Flowchart for program

23-Calculate the sum of series of even numbers

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