# Free Electronic Circuits & 8085 projects

## 2-Digit BCD to binary conversion

Published on Nov 18 2009

Statement: Convert a 2-digit BCD number stored at memory address 2200H into its binary equivalent number and store the result in a memory location 2300H.

Sample problem 1:

(2200H) = 67H

(2300H) = 6 x OAH + 7 = 3CH + 7 = 43H

 Source program : LDA 2200H : Get the BCD number MOV B, A : Save it ANI OFH : Mask most significant four bits MOV C, A : Save unpacked BCDI in C register MOV A, B : Get BCD again ANI FOH : Mask least significant four bits RRC : Convert most significant four bits into unpacked BCD2 RRC RRC RRC MOV B, A : Save unpacked BCD2 in B register XRA A : Clear accumulator (sum = 0) MVI D, 0AH : Set D as a multiplier of 10 Sum:   ADD D : Add 10 until (B) = 0 DCR B : Decrement BCD2 by one JNZ SUM : Is multiplication complete? i if not, go back and add again ADD C : Add BCD1 STA 2300H : Store the result HLT : Terminate program execution Flowchart for program

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